Masteringphysics: Ch 24 HW Google Chrome Secure https://session teringphysics co

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Masteringphysics: Ch 24 HW Google Chrome Secure https://session teringphysics com/myct/itemview? assignmen 71939881Beoffiata ned mast signed in as Mandeep Pabla University Physics 4B Electricity and Magnetism Problem 24.63 23 of 25 Problem 24.63 Part A Ci 400 pF and Ca 8.00 pF what must the capacitance Ch be A potential difference Va 490 V is applied across the the network is to store 2.50 10-3 Jofeiecnical energy? capacitor network of the following figure (Egure 1) Express your answer with the appropriate units. Value Units Submit My Answers Give up Faure 1 of 1 Eertaa Continue HHh

Explanation / Answer

Energy U = 0.5CV2

2.5*10^-3 = 0.5C*492

C = 2.08*10^-6 F

Which is the equivalent capacitance

Solving C1 and C2 in series we get C12 = 2uF

Solving C12 and C3 in parallel we get 2+C3 uF

Solving C123 and C4 in series

Ceq = (2+C3)8/(2+C3+8)

2.08*(10+C3) = 16+8C3 (solving in units of 10^-6 F)

4.8 = 5.92C3

C3 = 0.81 uF

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