Part A What is the magnitude of the torque on the circular current loop? Express

Question

Part A

What is the magnitude of the torque on the circular current loop?

Express your answer with the appropriate units.

Part B

What is the loop's stable equilibrium position?

What is the loop's stable equilibrium position?

The dipole will be in equilibrium after rotating clockwise 45. The dipole will be in equilibrium after rotating clockwise 135. The dipole will be in equilibrium after rotating clockwise 90. The dipole will be in equilibrium after rotating clockwise 180. o Wire 2.0 A 2.0 mm 0.20 A

Explanation / Answer

magnetic dipole u = I*A

A = area of loop =pi*R^2

R = radius of loop = 2mm/2 = 1 mm = 0.001 m

I = current in the circular loop = 0.2 A

u = 0.2*pi*0.001^2 = 6.28*10^-7 Am^2

magnetic field due to wire B = mue0*i/(2*pi*r)

B = 4*pi*10^-7*2/(2*pi*0.03) = 1.33*10^-5 T

torque = B*u*sin90

torque = 1.33*10^-5*6.28*10^-7

torque = 8.35*10^-12 Nm <<<------------answer

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part B

The dipole will be in equilibrium after rotating clockwise 90

angel between the magnetic dipole and magnetic field becomes 0

torque becomes zero

the position is stable

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