Part A What is the masimum amount in moles of PsOs that can theoresically be mad
ID: 704034 • Letter: P
Question
Part A What is the masimum amount in moles of PsOs that can theoresically be made from 211 g of Ps and excess oxypen? Express your answer to three significant figures and include the appropriate units View Available Hints) 340 mol Learning Goal: To calculane theoetical and percent yields given the masses of multiple reactants A balanoed chemical reaction gives the mole ratios benween reactants and products. For example one mole of white pheghorus. P. reacts with he moles of oxygen. Oy, to produce two moles of dphosphonus pentoxide PsOs In this example. e know the numiber of moles o phosphorus, we know that twice that much product can be made, assuming we have enough axygen Similarty, E we know the number of moles of arygen, we know that two-liths that much product can be Correct Part B Staton w ?? are gven the mole amounts of both reactants, you should do this type of caloulation ndividually for each one inding two difflerent values for the amount of product The smaller of these two values is the maximum amount of product that can be made, also known as the theoretical yield What is the maxcimum amount in moles of P Express your answer to three significant figures and include the appropriate units View Available Hints) 00 mol Os that can theoresically be made from 240 g of Os and excess phosphonus? If you are given the masses of the reactants, you wl first have to convert to moles Once you have mole amounts, you can follow the procedure described above, applying the ratios shown in the balanced chemical equation Correct Part C formed from the given amount of phosphorus and excess mal P,O)formed Son, tegen rondoygen aryger. In Pan B you find the amount ofproue (3 formed from the given amount of axygen and excess Now detemine how many moles of POs are produced from the given amounts of ghosphonus and arygen Express your answer to three significant figures include the appropriate units View Available Hints 27.35 % Submit X , Incorrect Try Again; 4 attempts remaining Part D This question will be shown after you complete previous queistions)Explanation / Answer
In part (c),the oxygen content is 240 g and P4 is 211 gm.
Given that is part(a) 3.4 moles of P2O5 produced and in part(b) 3 moles of P2O5 podueces.
Therefore from the 240g of oxygen ,the maximum P2O5 can be produced are 3 moles. therefore here oxygen is the limiting agent and P4 is in excess.
therefore 3 moles of P2O5 can be produces from given amount of oxygen and phosphorus.