Class Management I Help mwk 10 Circuits Begin Date: 3/24/2017 12:00:00 AM Due Da
ID: 1614755 • Letter: C
Question
Class Management I Help mwk 10 Circuits Begin Date: 3/24/2017 12:00:00 AM Due Date: 4/21/2017 10:00:00 PM End Date: 5/31/2017 12:00:00 AM (17%) Problem 7: An electric water heater consumes 5.5 kW for 2.15 h per day. P What is the cost in of running it for one year if electricity costs 105 cents/kWh? Grade Summary cost/yr Deductions 09 Potential 1000 Late work 50% Late Potential 509 sino coso tan0 7 8 9 4 5 6 cotano asino acos0 Submissions Attempts remaining: 7 acotan0 sinh0 1 2 3 atan0 per attempt) cosho l tanh0 cotanh0 O Degrees Radians Feedback os deduction per feedback. Hints 2 for a 0 deduction, Hints remaining 0 -Treat this as a conversion problem, so make the final units Syr. -So the information you need will be how many hours each day is it being run, how many days there are in a year,and bow expensive is each kWh. All contre C2017 Expert TA, LLCExplanation / Answer
Cost Consumed will be
Cost/yr = Power*time*Cost/kWh
Using the given values:
10.5 cents = 0.105 dollars
Cost/yr = 5.5 kW*(2.15 h/d)*(365 d/yr)*(10.5 dollars/kW-h)
Cost/yr = $526.97