Imagine a single-loop circuit with a battery, two wires, and a 10 Ohm resistor.

Question

Imagine a single-loop circuit with a battery, two wires, and a 10 Ohm resistor. The wires are also ohmic, but with a resistance much smaller than the 10 Ohm resistor. Despite the disparity in resistance, the current in the wire is the same as that through the resistor since they are in series. Using Ohm's Law, explain how this uniformity in current relates to (or arises from) the individual potential differences across the wire and resistor. Please explain this question in words rather than work, thank you.

Explanation / Answer

Suppose the wires have a resistance of r1 and r2.

So now they are in series, so if the same curren passing through them is I

The potential difference across resistor-1 V1 = IXr1

The potential difference across resistor-2 V2 = IXr2

The potential difference across resistor-1 V1 = IX10 = 10 I

So, this is how we can calculate the potential difference across each resistor with the same current I.

I hope this explains.

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