Physics 2 Lab 6 Ohm\'s Law data for the probes on the battery first. R- 1.33-45.
ID: 1644916 • Letter: P
Question
Physics 2 Lab 6 Ohm's Law data for the probes on the battery first. R- 1.33-45.11. Then l moved the probes to the light bulb and got, R = 31, 25.10.1 then added the (V) potentials; 60V & 33.33 1V and calculated for resistor potential & resistance. 60V+33. 331V=34.66V. so that gives me R 31.66v = 26.060. 1.33A The objective of this lab is to determine the resistance of resistors by applying Ohm's Law Become familiar with the use of a digital voltmeter and a digital ammeter to measure voltage and current; and tesing the validity of Ohm's law CurrentCircuit Circuit Resistor Resistor PotentiaResistance PotentiaResistance Potential Resistance Materials · Laptop . Pencil - Notebook - Calculator 1.04 0.99 57.7 60.61 26.069 24.716 25.9 25.0 86.07 84.72 82.76 85.57 60 For this trial, I moved the resistivity slider to about midway, which is located in the bottom right hand corner of the lab. The wire will now have some resistance of its own by doing this action. Same steps as the previous two above. For the first row of data, I did ohms law for resistance. R 57.7 ohms. Then by switching the probes to the light bulb, I calculated R- 26.069-= 25.9 ohms. Then added 60V+24.7 16V-86.07 . R = http://phet.colorado.edu/simulations/sims.php?sim-Circuit Construction_Kit DC Only Apparatus 86.07-= 82.76 ohms. Stretching 1.044 a wire junction, the amp declined to 0.99 A. My calculations were as follows, R 60.62ohms.then R-6.069 85.57ohms 1.044 -= 25.0 ohms. 60V + 24.7 16V-84.72 V. R = 8472 Data Circuit Circuit Resistor (A) Potential Resistance PotentialResistance Potentia Resistance Conclusions 0.45 20 4.499 10 13.499 30 Ohm's law states that voltage is directly proportional to current. Using Ohms Law for the trials, we can determine the resistance of the lab provided. To start, V(volts) 9 I(amps)-0.45 = 20 ohms. By switching the probes to the light bulb, R =-44 w = 10 ohms. Calculating the potential (V),I add the 9V and 4.4499V which equals 13.499 Calculating the resistance, did ohms law by R =-=-= 30 ohms 0454 045 CurrentCircuit Circuit Resistor Potentla ResistancePotenta Resistance Potenta Resistance 1.33 60 33.331 25.1 34.66 26.06 Using Ohms Law, I calculated this trial by Increasing the resistance of the light bulb to about 25Q, the resistor to about 20 and increasing the voltage of the battery to about 60. I did theExplanation / Answer
Your lab report is quite good and innovative. Method and conclusion is up to the mark. Apparatus used fulfilled all the requirements of the given lab.