Physics 2 homework help. I need steps, a simple steps. Thank you At left, a very
ID: 1438354 • Letter: P
Question
Physics 2 homework help. I need steps, a simple steps. Thank you
At left, a very thin hollow conducting spherical shell (radius = a) which has a total excess charge of (+Q) is at the center of a thick hollow spherical conducting shell (inner radius = b ; outer radius = c) having a total excess charge of (-Q). a. What is the electric field in the region 0 r a? b. What is the electric field in the region a r b? c. What is the electric field in the region b r c? d. What is the electric field in the region r c? e. Show that the potential difference V_ab = (V_a - V_b) between points "a" and "b" in the figure is given by V_ab=Q(bb-a)/4pi _0 ab f. Use the definition of capacitance (i.e. C = Q/V_ab) to show that the capacitance of this system is given by C= 4pi_0 ab/(b-a)Explanation / Answer
a) E=0 because electric field inside conducting shell is zero
b)E = kQ/r2 Here electric firld due to larger sphere will be zero because of the above mentioned reason but not due to inner sphere as is lying out of inner sphere
c)E = 0 E inside a conductor-wall is always zero, also charge -Q of outer sphere will lie on inner wall, so Qenclosed will be Q-Q =0, which gives E=0
d)E=0 because Qenclosed = Q-Q=0. hence by Guass Law, E =0
e) Va = kQ/a+ k(-Q)/b
Vb = kQ/b + k(-Q)/b =0
Va - Vb = kQ/a+ k(-Q)/b -0 = kQ/a -Kq/b = kQ(b-a)/ab
=Q (b-a)/ [4pi eo ab] HENCE SHOWN
f) C= Q/Vab = Q/[ Q (b-a)/ [4pi eo ab]]
=4pi eo ab / (b-a) HENCE SHOWN