Consider the situation shown in the figure below. An electric field of 300 V/m i

Question

Consider the situation shown in the figure below. An electric field of 300 V/m is confined to a circular area d = 10.9 cm in diameter and directed outward perpendicular to the plane of the figure. Consider that the field is increasing at a rate of 19.8 V/m middot s. (a) What is the direction of the magnetic field at the point P, r = 15.5 cm from the center of the circle? upwards downwards (b) What is the magnitude of the magnetic field at the point P, r = 15.5 cm from the center of the circle? T

Explanation / Answer

Here ,

a) the direction of magnetic field is upwards

b) for the magnetic field B

2pi * r * B = E * area of cirle

2pi * 0.155 * B = 19.8 * pi * (0.109/2)^2

solving for B

B = 0.19 T

the magnetic field is 0.19 T

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