Assignment 2 Problem 27.15 « previous 8 of 10 next » Problem 27.15 A 3.0 cm × 3.
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Assignment 2
Problem 27.15
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Problem 27.15
A 3.0 cm × 3.0 cm × 3.0 cm box with its edges aligned with the xyz-axes is in the electric field E =(370x+150)i^N/C, where x is in meters.
Part A
What is the net electric flux through the box?
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Problem 27.15
A 3.0 cm × 3.0 cm × 3.0 cm box with its edges aligned with the xyz-axes is in the electric field E =(370x+150)i^N/C, where x is in meters.
Part A
What is the net electric flux through the box?
= Nm2/CSubmitMy AnswersGive Up
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Explanation / Answer
Here ,
E = (370x + 150) i N/C
as the electric field is in x direction
the flux will be zero for the faces which are in xy and xz plane
flux will be only through yz plane
for the net flux
net flux = area of face * ((electric field at x = 0.03 m) -(electric field at x = 0))
net flux = 0.03^2 * ((370 * 0.03 + 150) -(370 * 0 + 150))
net flux = 9.99 *10^-3 N.m^2/C
the net electric flux through the box is 9.99 *10^-3 N.m^2/C
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