Picket Fence Free Fall r h for the l h. How is this rela DATA TABLE Trial (m a)
ID: 1655922 • Letter: P
Question
Picket Fence Free Fall r h for the l h. How is this rela DATA TABLE Trial (m a) ts.asq. 18.031 loro 9.5 o 9.lu4) Average ration (mis, j 8.9801-10-140- 4.420 1.420 ±0.444ms' due to gravity,g .91-420 19.81 ANALYSIS 1. From your six trials, determine the minimum, maximum, and average values for the acceleration of the Picket Fence. Record them in the data table. 2. Describe in words the shape of the position vs. time graph for the free fall. 3, Describe in words the shape of the velocity vs. time graph. How is this related to the shape or- The hme intased the position vs. time graph? Im and ten Connnved to increasesunes un, The average acceleration you determined represents a single best value, derived from all your measurements. The minimum and maximum values give an indication of how much the measurements can vary from trial to trial; that is, they indicate the precision of your measurement. One way of stating the precision is to take half of the difference between the minimum and maximum values and use the result as the uncertainty of the measurement. Express your final experimental result as the average value, ± the uncertainty Round the uncertainty to just one digit and round the average value to the same d 4. l place. For example, if your minimum, average, and maximum values are 9.12,9.93, and 10.84 m/s, express your result as g-9.9 ± 0.9 ms. Record your values in the data table. 5. Express the uncertainty as a percentage of the acceleration. This is the precision of your experiment. Enter the value in your data table. Using the exampl the precision would be e numbers from the last step 0.9 ×100% = 9% 9.9 Compare your measurement to the generally accepted value of g (from a textbook or other source). Does the accepted value fall within the range of your values? If so, your experiment 6. agrees with the acetd ues,itwas less than re auuaptes valve. 7. Inspect your velocity graph. How would the associated acceleration vs, time graph look? Sketch your prediction on paper. Now change the upper graph to acceleration vs. time. To do this, click the y-axis label and select Acceleration. want to rescale the graph so that the acceleration axis begins at zero. on any differences. You may Physics with VernierExplanation / Answer
1. here instead of plotting position with t^2, and getting a linear fit and finding a slope to get g, we have to do parabolic fit on the data and find out the coefficent of t^2 to find the acceleration.
2. Dropping the picket fence from higher above the Photogate will change the initial and the final velocities with which it crosses the photogates, but it wont change the time taken for the fence to cross the photogate, which was the only measured quantity in addition to teh distance between the photogates. Hence no measurable quantities will change if it is dropper from any different height
3. Throwing picket fence downwards or upwards will again have no effect on the measured quantity, time, but again the initial velocity while the fence enters the photogate and final velocity with which it leaves the photogate will change, but again they are not measured quantities.
4. Adding air resistance will change the time picket fence takes to cross the gates and if and when the normal formula for kinematics is used to get a value for g, we will get a different value for g which will be lower than the standard expected value
5. Value of g depends on altitude to a great extent. It also depends on latitude. Value of g decreases with increase in altitude and it increases with increase in latitude. The change in value of g due to increase in latitude is because of 2 reasons:
1. radious of earth is not constant, but it is more at equator than at poles
2. the rotation of earth reduces the value of g to some extent but with increasing latitide, the radius of the circle about the axis of earth decreases and the factor by which the value of g was decreasing decreases too, hence value of g increases