Consider three blocks, labelled A, B, and C, resting on a frictionless table as

Question

Consider three blocks, labelled A, B, and C, resting on a frictionless table as shown in in the Figure below. Assume the boxes have mass m_A = 7.13 kg, m_B = 2.93 kg, and m_C = 6.64 kg and they are acted on by a force labelled F with magnitude of 40.1 N and a direction as shown in the Figure. What is the acceleration of block B in the x direction, expressing your answer in units of m/s^2 ? Answer: For reasons that amount to "it seemed like a good idea at the time, " two fourth-years decide to transport a box of food and drinks across an icy lake to get to a party. They decide that the most effective

Explanation / Answer

All the 3 masses will move with a common acceleration given by:

a = Force / Total mass

a = 40.1 / (7.13 + 2.93 + 6.64) = 2.4 m/s^2

Ans: acceleration of Block B = 2.4 m/s^2

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