Part A Determine the equivalent resistance of the \"ladder\" of equal 175- resis

Question

Part A

Determine the equivalent resistance of the "ladder" of equal 175- resistors shown in (Figure 1) . In other words, what resistance would an ohmmeter read if connected between points A and B?

Express your answer to three significant figures and include the appropriate units.

art B

What is the current through resistor a if a 50.0-V battery is connected between points A and B?

Part C

What is the current through resistor b?

Express your answer to three significant figures and include the appropriate units.

Part D

What is the current through resistor c?

Express your answer to three significant figures and include the appropriate units

Explanation / Answer

Here , for the net resistance of the circuit

for the right 3 R in series

R1 = 3R

for R1 and R in parallel

R2 = 3R * R/(3R + R)

R2 = 0.75*R

for R , R , 0.75R in series

R3 = R + R + 0.75R = 2.75 * R

for R3 and R in parallel

R4 = 2.75*R * R/(2.75R + R)

R4 = 0.688*R

for the net resistance

Req = R + R + 0.688 R

Req = 2.688 * R

part B)

current through resistor a = V/Req

current through resistor a = 50/(2.688 * 175)

current through resistor a = 0.106 A

part C)

using current divider

current in resistor b = 2.75*R/(2.75R + R) * 0.106

current in resistor b = 0.078 A

part D)

as current in a is equal to current in c

current in c = 0.106 A

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