Please help !!! An Insulated Thermos contains 109 cm3 of hot coffee at 90.0°C. Y

Question

Please help !!! An Insulated Thermos contains 109 cm3 of hot coffee at 90.0°C. You put a 12.0 g ice cube at its meting point to cool the coffee. By how many degrees has your coffe My Not is reached? Treat the coffee as though it were pure water and neglect energy exchanges with the environment eC Additional Materials Section 18.4 1 points HRW10 18 P.040 My Noto e the specific heat of a metal from the following data. A container made of the metal has a mass of 3.0 kg and contains 12 kg of water. A 2.1 kg piece of the metal initially at a temperature of 190°C is dropped into the water. The container and water intialily have a temperature of 13.0°C, and the final temperature of the entire system is 18.0°C Additional Materials

Explanation / Answer

1.

apply the principle of calorimetry as

heat lost by Coffee = Heat gained by ice

mass of Coffee = 109 g

so

heat lost by Coffee Q= m c DT

let T be the final temperature then

Qof Coffee = 109 * 1 * (90-T)

Heat gained by Cube = ML + MCDT

HEat gained by Cube = (12 * 340) + (12 * 1 * (T-0))

finally    109 * 1 * (90-T) = (12 * 80) + (12 * 1 * (T-0))

T = 73.14 deg C

----------------

2. heat LOST by metAL = HEAT gained by metal and mass

m c dT = M cm dT + m * c(water) * dT

2100* c * (190-18) = (3000* c * (18-13) + (12000* 4.2 * (18-13)

c = 727 kJ/Kg C

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