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If a ball is being swung in avertical circle at the end of a light cord at a con

ID: 1663177 • Letter: I

Question

If a ball is being swung in avertical circle at the end of a light cord at a constant speed of3.35m/s when the the radius of the vertical circle is 0.70m and themass of the ball is 0.160kg calculate the tension in the cord atthe top of the swing---------- so what i did is: m=0.160kg v=3.26m/sr=0.7m fc=T+fg ---- T=fc-fg------T= (mv2/r) - mg now what confuses me is that thisequation is used for tension in the cord at the bottom ofthe circle and it gives me the same answer what can i do to get adifferant answer for tension in the cord at the top of thecord If a ball is being swung in avertical circle at the end of a light cord at a constant speed of3.35m/s when the the radius of the vertical circle is 0.70m and themass of the ball is 0.160kg calculate the tension in the cord atthe top of the swing---------- so what i did is: m=0.160kg v=3.26m/sr=0.7m fc=T+fg ---- T=fc-fg------T= (mv2/r) - mg now what confuses me is that thisequation is used for tension in the cord at the bottom ofthe circle and it gives me the same answer what can i do to get adifferant answer for tension in the cord at the top of thecord If a ball is being swung in avertical circle at the end of a light cord at a constant speed of3.35m/s when the the radius of the vertical circle is 0.70m and themass of the ball is 0.160kg calculate the tension in the cord atthe top of the swing---------- so what i did is: m=0.160kg v=3.26m/sr=0.7m fc=T+fg ---- T=fc-fg------T= (mv2/r) - mg now what confuses me is that thisequation is used for tension in the cord at the bottom ofthe circle and it gives me the same answer what can i do to get adifferant answer for tension in the cord at the top of thecord

Explanation / Answer

http://www.physicsforums.com/showthread.php?p=2530028 Hope this helps!