I\'m stuck on this problem: Suppose you had two small boxes, each containing 1.0
ID: 1664153 • Letter: I
Question
I'm stuck on this problem:Suppose you had two small boxes, each containing 1.00 g ofprotons. If one were placed on the moon by an astronaut and the otherwere left on the earth, and if they were connected by a very light(and very long!) string, what would be the tension in the string?Express your answer in newtons and in pounds. I came up individually with F (box onearth)= .0098N and F (moon)=.00162N, but not sure if these areright or what to do with them to find the tension. Do you need to take into account the gravitational forces ofthe earth and moon on the protons? Why? I was thinking yes since thegravitational force on the moon is 1/6th of the Earth's and wouldaffect the weight. What gravitational force would each box of protons exert onthe other box? Is this answered by Coulomb'sLaw? Thanks in advance for the help. I'm stuck on this problem:
Suppose you had two small boxes, each containing 1.00 g ofprotons. If one were placed on the moon by an astronaut and the otherwere left on the earth, and if they were connected by a very light(and very long!) string, what would be the tension in the string?Express your answer in newtons and in pounds. I came up individually with F (box onearth)= .0098N and F (moon)=.00162N, but not sure if these areright or what to do with them to find the tension. Do you need to take into account the gravitational forces ofthe earth and moon on the protons? Why? I was thinking yes since thegravitational force on the moon is 1/6th of the Earth's and wouldaffect the weight. What gravitational force would each box of protons exert onthe other box? Is this answered by Coulomb'sLaw? Thanks in advance for the help.
Explanation / Answer
no, you are wrong. First question, the tension of the string should be the electricforce that is caused between two boxs. T=kq^2/r^2 mass of proton is 1,67*10^-27 kg , charge of a proton is 1,6*10^-19C so if the box is made by proton so number of protonN=1/1,67*10^-24 so the charge is N*1,6*10^-19˜9,6*10^4(C) Distance between moon and earth is3,82*10^8m so F=kq^2/r^2=568(N). ---- the gravity force is not needed to take into account because it isrelative small to F. ---- the gravity force between two box F1=Gm^2/r^2=4,57*10^-34 (N)