A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N.

Question

A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. (a) Find the work done by the force.
J

(b) Find the work done by gravity.
J

(c) Find the final kinetic energy of the box.
J A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. A 4.0 kg box is raised from rest adistance of 3.0 m by a vertical force of120 N. (a) Find the work done by the force.
J

(b) Find the work done by gravity.
J

(c) Find the final kinetic energy of the box.
J (a) Find the work done by the force.
J

(b) Find the work done by gravity.
J

(c) Find the final kinetic energy of the box.
J (a) Find the work done by the force.
J

(b) Find the work done by gravity.
J

(c) Find the final kinetic energy of the box.
J

Explanation / Answer

( (a) Workdone W = Fdcos =mghcos = 120*3.0 cos =  360 J (b) Workdone by gravity = mgh = 4*9.8*3.0 = -117.6 J (c) The final kinetic energy is equal to from workenergy theorem                             Thenet workdone = change in kinetic energy       Therefore the kineticenergy = 242.4 J (b) Workdone by gravity = mgh = 4*9.8*3.0 = -117.6 J (c) The final kinetic energy is equal to from workenergy theorem                             Thenet workdone = change in kinetic energy       Therefore the kineticenergy = 242.4 J

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