A small domestic elevator has a mass of 454 kg and can ascendat a rate of 0.180 m/s. What is the average power that must besupplied for the elevator to move at this rate? (a)_____ W can someone please show me steps and the formulas that can beused to solve this problem? A small domestic elevator has a mass of 454 kg and can ascendat a rate of 0.180 m/s. What is the average power that must besupplied for the elevator to move at this rate? (a)_____ W can someone please show me steps and the formulas that can beused to solve this problem?
Explanation / Answer
P = E/t where E = energy P = W/t or F*d/t since Work = F*d since d/t = v, P is also = F*v P = 454kg*9.8m/s2 *.180m/s = 800.856W Hope that helps