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Consider a series RLC circuit with R = 15 ohm, L = 184 mH, C = 75 mu F, and a ma

ID: 1674978 • Letter: C

Question

Consider a series RLC circuit with R = 15 ohm, L = 184 mH, C = 75 mu F, and a maximum voltage of 149 V. What is the impedance of the circuit at resonance? Z = ohm What is the resonance frequency of the circuit? f = Hz When will the current be greatest: at resonance, at ten percent below the resonant frequency, or at ten percent above the resonant frequency? The current is a maximum at ten percent above the resonant frequency. The current is a maximum at ten percent below the resonant frequency. The current is a maximum at resonance. What is the rms current in the circuit at a frequency of 60 Hz? Irms = A

Explanation / Answer

   a.   Impedance   Z   =   {R2   +   (XL   -   XC)2}                               atresonance      XL   =  XC             =>   Z   =   R       Hence impedance atresonance      Z   =   15       b.   Resonancefrequency         f   =   1/ 2(L * C)                                                          =   1/ 2 * 3.14 * ( 184 * 10-3 * 75 *10-6)                                                          =   42.86   Hz    c.   Current   I   =   V/ Z          Clearlycurrent is maximum when Z is minimum, i.e. at resonance.             =>   Z   =   R       Hence impedance atresonance      Z   =   15       b.   Resonancefrequency         f   =   1/ 2(L * C)                                                          =   1/ 2 * 3.14 * ( 184 * 10-3 * 75 *10-6)                                                          =   42.86   Hz    c.   Current   I   =   V/ Z          Clearlycurrent is maximum when Z is minimum, i.e. at resonance.    d.   At 60Hz         XL   =   2* f * L                                        =   2* 3.14 * 60 * 184 * 10-3                                        =   69.33                                     XC   =   1/ 2 * 60 * 75 * 10-6                                        =   35.39          Z60   =   {152   +   (69.33   -   35.39)2}                =   37.11       I60   =   V/ Z60          =   149/ 37.11          =   4.015   A    Irms   =   I60/ 2             =   4.015/ 2             =   2.439   A          =   149/ 37.11          =   4.015   A    Irms   =   I60/ 2             =   4.015/ 2             =   2.439   A