Consider the electric field given by ~E =(2xi-3j) N/C, where x is in units of me

Question

Consider the electric field given by ~E =(2xi-3j) N/C, where x is in units of meters.
Now suppose we have a rectangular volume, a distance c from the y - z plane, with two edges length a and the third length b. The outgoing flux through the right surface
is:
1. right = -2 a b (a + c) .
2. right = -2 (a + c) .
3. right = -[2 (a + c) - 3] a b .
4. right = 2 (a + c) .
5. right = -3 a b .
6. right = [2 (a + c) - 3] a b .
7. right = 2 a b .
8. right = 2 a b (a + c) .
9. right = -2 a b .
10. right = 3 a b .

Explanation / Answer

The field parallel to the x-axis is 2 x The field at the surface is either 2 (c + a) or 2 (c + b) So the magnitude of the flux is either 2 (c + a) a b or 2 (c + b) a^2 The sign of the flux is negative since it is leaving the surface

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