Block A hangs over the left side of the table, and block C hangs over the right

Question

Block A hangs over the left side of the table, and block C hangs over the right side of the table, with a pulley on each table edge, and the string connecting them hangs over each pulley. Block B is in the middle of the table with a string on each side connected to block A and C.
Block A mass = 6.00 kg
Block B mass = 2.50 kg
Block C mass = 1.50 kg
The pulleys are ideal and there is no friction between block B and the table.
What is the tension in the string connecting blocks B and C?
Answer is 21.3 N, but I don't know how to solve this. Please answer in detail, showing all steps. Thanks!

Explanation / Answer

let tension be T1 and T2 ( string AB and string BC respectively). let a be acceleration rate of the system. 6g-T1=6a. T1-T2=2.5a T2-1.5g=1.5a. solve this we have. T1=32.34(N) T2=21.3(N) a=4.41(m/s). so its T2=21.3N

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