Could anyone possibly help me with this question? ? Resistance in the circuit sh
ID: 1720851 • Letter: C
Question
Could anyone possibly help me with this question??
Resistance in the circuit shown in Fig. 1.10 acts as a damping agent. Set R = 0 ohms in Eq. (1.5.23) and simply close the circuit that has a charge Q_0 C across the capacitor initially, but no current. The result should indicate a steady oscillation for all time. Plot, your result along with the results in Fig. 1.18 for the choice L = 1 henries and C = 4 faradays. Often resistance is very small in circuits and provided we consider the solution for a moderate time, the oscillatory solution is accurate, but it is not valid for very long times! Eventually the presence of resistance, no matter how small, will cause the oscillations to decay away. The temporal behavior of the charge on the capacitor for two choices of the resistance. Fig. 1.18 The charge density on the capacitor as a function of time. Voltage drop across each component must add up to balance the applied Let V_R = V_2 - V_1, V_L = V_3 - V_2 and V_C = V_4 - V_3 be the voltage drops of the resistor, the inductor and the capacitor, respectively. Then, V_L + V_R + V_C = E. current I A must be the same in all parts of the circuit. We must determine the voltage drop across the various components voltage drop across the resistor is V_R = I (t) R. The voltage drop across the is V_C = Q(t)/C, where Q(t) C is the charge on the capacitor - it can time. The voltage drop across the inductor is V_L = L DI(t)/dt. The first L DI/dt (t) + RI(t) + 1/C Q(t) = E(t).Explanation / Answer
the circuit diagram is missing...please provide all the necessary data then i will post the solution