Two balls are approaching each other head-on. Their velocities are+9.95 and-11.8

Question

Two balls are approaching each other head-on. Their velocities are+9.95 and-11.8 m/s. (a) Determine the velocity of the center ofmass of the two balls if they have the same mass.
Enter anumber. m/s

(b) Determine the velocity of the center of mass of the two ballsif the mass of one ball (v = 9.95m/s) is twice the mass of the other ball (v = -11.8 m/s).
Enter anumber. m/s (a) Determine the velocity of the center ofmass of the two balls if they have the same mass.
Enter anumber. m/s

(b) Determine the velocity of the center of mass of the two ballsif the mass of one ball (v = 9.95m/s) is twice the mass of the other ball (v = -11.8 m/s).
Enter anumber. m/s Enter anumber. Enter anumber.

Explanation / Answer

Given : .           Velocities u1 = 9.95 m /s   ; u2 = - 11.8 m /s .           Let masses of particles m1 = m2 = m . (a)      Velocity of center ofmass is : .               VCM   = m1 u1 + m2 u2 / ( m1 + m2) .                          =   ( 9.95 m - 11.8 m ) / 2m   = - 1.85 m / 2 m   = -0.925      m /s . (b)      Given m2 = 2 m1 = 2 m .               VCM   = m1 u1 + m2 u2 / ( m1 + m2) .                          =   ( 9.95 m - 11.8 *2m ) / 3m   = - 13.65 m / 3 m   = - 4.55      m /s . Here the negative sign represents the direction. . Hope this helps u! . .                          =   ( 9.95 m - 11.8 *2m ) / 3m   = - 13.65 m / 3 m   = - 4.55      m /s . Here the negative sign represents the direction. . Hope this helps u! .

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---