Can somebody please solve this step by step for me? In the figure below, a 1.0 g

Question

Can somebody please solve this step by step for me?
In the figure below, a 1.0 g bullet isfired into a 0.80 kg block attached tothe end of a 0.60 m nonuniform rod of mass 0.50 kg. Theblock-rod-bullet system then rotates in the plane of the figureabout a fixed axis at A. The rotational inertia of the rodalone about that axis at A is 0.060kg·m2. Treat the block as aparticle. (a) What then is the rotational inertia of theblock-rod-bullet system about point A?
1 kg·m2

(b) If the angular speed of the system about A just afterimpact is 4.5 rad/s, what is the bullet's speed just beforeimpact?
2 m/s

Explanation / Answer

The mass of the block Mb = 0.80 kg

mass of bullet mB = 1.0 g

mass of rod mr =  0.50 kg

Rotational inertia of rod Ir =  0.060kg·m2

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