Can somebody please show me how this problem isdone? I have no clue how to do it
ID: 1741206 • Letter: C
Question
Can somebody please show me how this problem isdone? I have no clue how to do it. Thanks a bunch. :) On planet Tehar, the free-fall acceleration isthe same as that on Earth, but there is also a strong downwardelectric field that is uniform close to the planet's surface. A2.01 kg ball having a charge of4.97 µC is thrown upward at a speedof 20.1 m/s. It hits the ground after an interval of 4.10 s. Whatis the potential difference between the starting point and the toppoint of the trajectory?Can somebody please show me how this problem isdone? I have no clue how to do it. Thanks a bunch. :) On planet Tehar, the free-fall acceleration isthe same as that on Earth, but there is also a strong downwardelectric field that is uniform close to the planet's surface. A2.01 kg ball having a charge of4.97 µC is thrown upward at a speedof 20.1 m/s. It hits the ground after an interval of 4.10 s. Whatis the potential difference between the starting point and the toppoint of the trajectory?
Explanation / Answer
The time of flight on object of mass 'm' thrownvertically up t = 2v / a from the aboveequaio n a = 2v / t here we can sovle for accelration ' a ' here we can sovle for accelration ' a ' by work energy theorem work done =change in kinetic energy W = F * h = mv^2 / 2 (at the point of maximum height) = m * a * h =mv^2 /2 from the above equaion we can sovle for height reached by themass m from the above equaion we can sovle for height reached by themass m = m* (g + a ') * h = m v^2 /2 = m* (g + qE/m )* h = m v^2 / 2. gh + qEh / m = v^2 / 2 gh + qEh / m = v^2 / 2 the potential difference between the starting point and the top point of the trajectory V= E*hv = projectedvelocity a = net accleration acting downward due to gravity and electric field. a = g + a ' a' = accleration due to electricfield a' = F/ m = qE /m m= mass of the obejct q = charge on themass E = electricfield g = accleration due togravity from the above equaion we cansovle for potential difference ' V '. v = projectedvelocity a = net accleration acting downward due to gravity and electric field. a = g + a ' a' = accleration due to electricfield a' = F/ m = qE /m m= mass of the obejct q = charge on themass E = electricfield g = accleration due togravity from the above equaion we cansovle for potential difference ' V '.