A 17 F capacitor is joined in series with a 32 Fcapacitor and a 12 Volts battery

Question

A 17 F capacitor is joined in series with a 32 Fcapacitor and a 12 Volts battery. What is the potential differenceacross each capacitor? V1? V2? What is the charge on each capacitor? Q1?
Q2? How much energy is stored by each capacitor? Energy in1? Energy in 2? A 17 F capacitor is joined in series with a 32 Fcapacitor and a 12 Volts battery. What is the potential differenceacross each capacitor? V1? V2? What is the charge on each capacitor? Q1?
Q2? How much energy is stored by each capacitor? Energy in1? Energy in 2?

Explanation / Answer

Given : C1 = 17F = 17 * 10-6F C2 = 32F = 32 *10-6 F V = 12 V 1/Ceq = 1/C1 +1/C2 2 ) Charge on capacitor    C = q1 / V    q1= C V 3 ) Energy stored ina capacitor U = 1/2 C V2 Solve it I hope it helps you

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---