Im stuck on this homework problem and I dont know how to goabout solving it. Cou
ID: 1757680 • Letter: I
Question
Im stuck on this homework problem and I dont know how to goabout solving it. Could you point me in the right direction? Hereis the problem. The combination of an applied force and a friction forceproduces a constant total torque of 36.0 N x m on a wheel rotatingavout a fixed acis. The applied force acts for 6.00s. During thestime, the angular speed of the wheelincreases from 0 to 10.0 rad/s.The applied force is then removed and the wheel comes to rest in60.0 s. Find (a) the moment of inertia of the wheel, (b) themagnitude of the frictional torque, and (c) the total number ofrevolutions of the wheel. Im stuck on this homework problem and I dont know how to goabout solving it. Could you point me in the right direction? Hereis the problem. The combination of an applied force and a friction forceproduces a constant total torque of 36.0 N x m on a wheel rotatingavout a fixed acis. The applied force acts for 6.00s. During thestime, the angular speed of the wheelincreases from 0 to 10.0 rad/s.The applied force is then removed and the wheel comes to rest in60.0 s. Find (a) the moment of inertia of the wheel, (b) themagnitude of the frictional torque, and (c) the total number ofrevolutions of the wheel.Explanation / Answer
total torque = 36.0 N x m, t = 6.00 s, angular speed from 0to = 10.0 rad/s. t' = 60.0 s. Find the moment of inertia of the wheel I, frictional torque' and the total number of revolutions of the wheelN applied force = F, friction force = f, = I( - 0)/t I = *t/ = 21.6 kg-m2 -' = I(0 - )/t' ' = 3.6 N-m during t, the angular displacement = (0 + )*t/2 during t', the angular displacement = ( + 0)*t'/2 total angular displacement = * (t + t')/2 = 330 rad N = 330/(2) = 52.5 rev