A small charged ball lies within the hollow of a metallic sphericalshell of radi

Question

A small charged ball lies within the hollow of a metallic sphericalshell of radius R. Here, for three situations, are the netcharges on the ball and shell, respectively: 1 +4q, 0 2 -6q, +10q 3 +16q, -12q (a) Rank the situations according to the charge on the innersurface of the shell, most positive first (use only the symbols> or =, for example 2=3>1).

(b) Rank the situations according to the charge on the outersurface, most positive first (use only the symbols > or =,for example 2=3>1).

***Please show all steps and formulas used because I don't knowwhere to begin***
1 +4q, 0 2 -6q, +10q 3 +16q, -12q 1 +4q, 0 2 -6q, +10q 3 +16q, -12q

Explanation / Answer

electric field inside the metallic shell = 0, so the sum of thecharge of the ball and that of the inner surface = 0 situation 1: charge of inner surface = -4q situation 2: charge of inner surface = 6q situation 3: charge of inner surface = -16q a) 2 > 1 > 3 b) 1 = 2 = 3 (+4q for each one)

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