I would really appreciate some help on this physics problem. Iwould like help wi

Question

I would really appreciate some help on this physics problem. Iwould like help with the solution of this prob, how to get theanswer not just the answer itself. I have a test coming upand I need material to study from. I made a diagram of theproblem, I just can't seem to get the forces right, i alwaysseem to end up that i need the mass of an object, but none isgiven, so you'd have to algebraically get rid of it, which i can'tseem to do. Any help would be appreciated. Thanks! In a "Rotor-ride" at a carnival, people pay money to berotated in a vertical cylindrically walled "room." If the roomradius is 5.4 m, and the rotation frequency is 0.6 revolutions persecond when the floor drops out, what is the minimum coefficient ofstatic friction so that the people will not slip down?

Explanation / Answer

The frictional force keeping the peopleagainst the wall is Fr = µ*Fc, where Fc is thecentrifugal force pushing the people against the wall. Centrifugalforce is found with:
--
Fc = m*r*^2, where is the angular velocity inradians per second.
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You are given that the rotation rate is 0.6 revolutions per second.One revolution has 2* radian, so = 0.6*2* rad/secso, --
Fc = m*(5.4)*(0.6*2*)^2
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and Fr = µ*Fc = µ*m*(5.4)*(0.6*2*)^2
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This must equal the weight of the person, W = m*g:
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m*g = µ*m*(5.4)*(0.6*2*)^2
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µ = g / (5.4)*(0.6*2*)^2
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µ = __________ -- -- Hope this helps.

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