Perhaps the most-common gravitational calculation is to determine the \"weight\"

Question

Perhaps the most-common gravitational calculation is to determine the "weight" of an object of mass mo sitting on the surface of the earth (i.e., the magnitude of the gravitational attraction between the earth and the object) According to Newton's law of universal gravitation, the gravitational force on the object is where me is the mass of the earth and re is the distance between the object and the center of the earth (i.e., re = radius of the earth = 6.38 x 103 km). Part F What is the value of the composite constant (Cm)to be multiplied by the mass of the object mo equation above? Express your answer numerically in meters per second per second. in the m/s Submit My Answers Give Un Provide Feedback Continue

Explanation / Answer

f) G = 6.674 * 10^ -11 m3 kg-1 s-2 , me = 5.972 * 10^24 kg

G me / re2 = 6.674 * 10^ -11 * 5.972 * 10^24 / (6.38* 10*6)^2

= 9.80 m /s2

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