Class l Help HW 12 Begin Date: 10 30/2017 11:00:00 AM- -Due Date: 11/13/2017 11:
ID: 1780992 • Letter: C
Question
Class l Help HW 12 Begin Date: 10 30/2017 11:00:00 AM- -Due Date: 11/13/2017 11:00:00 AM End Date: 11/13/2017 11:00:00 AM 10% Problem 7: A sump pump (used to drain water from the basement of houses built below the water table is draining a flooded basement at the rate of 0. 75 Ls, with an output pressure of 2.8 x 10 N/m 5096 Part (a) The water enters a hose with a 3.4 cm inside diameter and rises 2.4 m above the pump. What is its pressure at this point N/m22 You may neglect frictional losses. Grade Summary 0% 100% sin0 cos0 Submissions Attempts remaining: (5% per attempt) detailed view +1 2 3 ac cosh0 tnhcotanh0 Degrees C) Radians Subemit Hint I give up! Hints: 1 % deduction per hint. Hints remaining: 4 Feedback: 1% deduction per feedback. 50% Part (b) The hose goes over the foundation wall, losing 0.25 m 1n height and widens to 4.3 cm in diameter. What is the pressure now in N/m*? You may neglect frictional losses. All conteut 2017 Expect TA, LLCExplanation / Answer
A)
from bernoullis eqution.
P1+1/2d*v1*v1 + d*g*h1 = P2+1/2d*v2*v2 + d*g*h2.
2.8*10^5 + 1000*9.8*h1 = P2 + 1000*9.8*h2.
h2 - h1 = 2.4m.
so
2.8*10^5 +1000*9.8*(-2.4) = p2.
p2 = 256480 N/M2.
= 2.6*10^5 N/M2.
SINCE AREAS are same v1 = v2 ....as A1*v1 = A2*v2.
B)
using the same bernouliis equation.
P1+1/2d*v1*v1 + d*g*h1 = P2+1/2d*v2*v2 + d*g*h2.
2.8*10^5 + 1000*9.8*h1 = P2 + 1000*9.8*h2.
h2 - h1 = 3-0.25=2.75 m
so
2.8*10^5 +1000*9.8*(-2.75) = p2.
p2 = 253050 N/M2.
= 2.5*10^5 N/M2.
Please don't forget to rate positively if you found this response helpful. Feel free to comment on the answer if some part is not clear or you would like to be elaborated upon. Thanks and have a good day!