Consider the circuit shown in the diagram below. Switch 1 has been closed for a
ID: 1788260 • Letter: C
Question
Consider the circuit shown in the diagram below. Switch 1 has been closed for a long time. The capacitor is initially uncharged.
1. Consider the circuit shown in the diagram below. Switch 1 has been closed for a long time. The capacitor is initially uncharged. S2 S1 Now switch S2 is closed. What happens to the brightness of (current through) each of the bulbs immediately after switch S2 is closed? Explain your reasoning. a. b. Compare the brightness of the bulbs after switch S2 has been closed for a long time. Explain your reasoning. If, after the switch S2 has been closed for a long time, switch Si is then opened, how would the brightness of the bulbs compare over time? (Switch S2 remains closed.) Explain your reasoning. c.Explanation / Answer
(A) Current will pass through Capacitor, while Bulb "B" will not get current. Therefore, brightness of bulb "A" increases, while Bulb "B" will have no brightness.
(B) After long time, when Capacitor gets fully charged, again we have the initial situation, when only Bulb A & B will get the Current, hence Brightness of both Bulbs will become same as initially when Switch S2 was not connected.
(C) When Switch S1 is opened, Current through battery stops, therefore Bulb "A" will stop glowing, while Bulb "A" will still glow from the current supplied by Capacitor, but as Capacitor discharges, brightness of bulb "B" reduces.