Consider the circuit shown in Figure P18.8. Calculate the equivalent resistance

Question

Consider the circuit shown in Figure P18.8. Calculate the equivalent resistance of the 10.0- ohm and 5.00-ohm resistors connected in parallel. Using the result of part (a), calculate the combined resistance of the 10.0-ohm, 5.00-ohm, and 4.00-ohm resistors. Calculate the equivalent resistance of the combined resistance found in part and the parallel 3.00-ohm resistor. Combine the equivalent resistance found in part (c) with the 2.00-ohm resistor. Calculate the total current in the circuit. what is the voltage drop across the 2.00-s resistor? subtracting the result of part from the battery voltage, find the voltage across the 3.00-ohm resistor. Calculate the current in the 3.00-ohm resistor. Consider the circuit shown in Figure P18.9. Find

Explanation / Answer

Net Resistance in Series = R1 + R2 ..............

Net Resistance 1/Rnet = 1/R1 + 1/R2 ......................

part A :

10ohms and 5 ohms are in parallel

1/Rp1 = 1/5 +1 /10

Rp1 = 3.34 ohms

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part B :

Rp1 is in series with 4 ohms

so

Rs1 = 4 + 3.34 = 7.34 ohms

--------------------------------

part C:

this Rs1 is in parallel with 3 ohms

so

1/Rp2 = 1/3 + 1/7.34

Rp2 = 2.13 ohms

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part D :

Rp2 is in series = 2 ohms

Rs2 = Rnet = 2 + 2.13 = 4.13 ohms

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part E:

Current Inet = Vnet/Rnet

Inet = 8/4.13

Inet = I across 2 ohms = I across Rp2 = 1.94 Amps
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part F :

Vacross 2 ohms = i * R

V across 2 ohms = 1.94 * 2

V2 = 3.87 Volts

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Part G :

Vacross P2 = V across Rs1 = R across 3 ohms (as they are connected in parallel

this V = 8 - 3.87

V across 3 ohms = 4.12 Volts

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part H:

Iacross 3 ohms = V/R

Iacrs 3 ohms = 4.13/3 = 1.375 Amps

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