Consider the circuit shown in Figure 1-43. Assume that the switch has been open
ID: 1810681 • Letter: C
Question
Consider the circuit shown in Figure 1-43. Assume that the switch has been open for a long time and that V1 = 5 V and V2 = 0 V. If the switch is closed and we wait a long time, (a) find the final voltage across the two capacitors, assuming that energy is conserved, and (b) find the final voltage across the two capacitors, assuming that charge is conserved. (c) Compare the two answers from parts (a) and (b). Can you explain why they are different? Hint: Think of the models used. Is there anything you could do to more accurately model the operation of a real circuit?Explanation / Answer
if energy is conserved -
C1*25 = (C1+C2)*V^2
=> V =sqrt(25C1/(C1+C2))
if charge is conserved
V = 5*C1/((C1+C2)
These are different because energy is not conserved. While transferring the charge to other capacitor, loss of the energy occurs.