Consider the circuit shown in Figure 1 . The batteries have emfs of E 1 = 9.0 V

Question

Consider the circuit shown in Figure 1. The batteries have emfs of E1=9.0V and E2=12.0V and the resistors have values of R1=28?, R2=65?, and R3=37?.

Part A: Determine the magnitudes of the currents in each resistor shown in the figure. Ignore internal resistance of the batteries. Express your answers using two significant figures separated by commas.

Part B: Determine the magnitudes of the currents in each resistor shown in the figure. Assume that each battery has internal resistance r = 1.0 ?. Express your answers using two significant figures separated by commas.

Part C: Determine the directions of the currents in each resistor. Assume that each battery has internal resistance

r = 1.0 ?.

Explanation / Answer

A)

9-28*I1-65*(I1+I3) =0

12-37*I3-65*(I1+I3) =0

12-102*I3-65/93*(9-65*I3)= 0

I3 = (12-65*9/93)/(102-65*65/93)

= 0.101 A

I1 = (9-6.56)/93

=0.0262 A

so

I1= 0.026 A

I2=0.127 A or 0.13 A

I3 = 0.101 A

b)

9-29*I1-65*(I1+I3) =0

12-38*I3-65*(I1+I3) =0

12-103*I2-65/94*(9-65*I2)= 0

I3 = (12-65/94*9)/(103-65*65/94)

0.0995 A

I1 = 0.027 A

so

I1 = 0.027 A

I2 = 0.126 A

I3 = 0.0995 A

c)

A. I1right, I2 left, I3 up

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