The figure below shows two long parallel, straight wires carrying currents, 11 =

Question

The figure below shows two long parallel, straight wires carrying currents, 11 = 16 A and 12 = 8 A. The distance between the wires is 4 m. What is the magnitude of the magnetic field (in nT) at point A, which is at a distance of 16 m from wire #1? 266.7* 1 0.9 (in units of nT or nanoteslas) Remember that a long, straight wire carrying current I1 produces a magnetic field B1 at a radial distance r1 from the wire given by: BI-Hol 1 / (2nr1), where the constant 0/2n = 2e-7 T m/A. >>Do not forget to convert the answer in Teslas to nanoTeslas by multiplying by 109 In this problem, you will need to separately calculate B1 and B2 due to wires #1 and #2, respectively. These two magnitudes should be added because the currents are in identical directions for the wires. >>Do not forget that the radius r2 used to calculate the magnetic field B2 for wire #2 is the SUM of the two given distances (r1 + distance between wires). Submit Answe Incorrect. Tries 1/2 Previous Tries

Explanation / Answer

Bnet=B1+B2

Bnet = µ0I1/2r1 + µ0I2/2r2

Plugging values,

Bnet = (4*10^-7*16)/(2*16) + (4*10^-7*8)/(2*20)

Bnet = 2.8*10^-7 T

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