Could someone please answer this question neatly with small step-by-step notes s

Question

Could someone please answer this question neatly with small step-by-step notes so that I understand how to solve the problem. I missed 2 weeks of school because I was very sick and I am very behind. I greatly appreciate the help! Thank You!

Pl. The capacitors in the figure have values: C1-1.00 F , C2-2.00 aF, C,-3.00 uP. All three capacitors are initially uncharged. The switch S on the figure is first connected at position A so that the battery of voltage V -12.0V can charge capacitor C, with a charge q a. (4) Calculate the charge q, on the capacitor C3 b. (3) Calculate the total energy U of all three capacitors when the switch S is connected to point A. c. (4) Now, assume that the C, is a parallel plate capacitor and immersed in a material with the dielectric constant x-3.00. Calculate the new charge q3eW on this capacitor Now the switch S is in position B and the capacitor C, is without the dielectric material d. (9) Determine the new charges q, qh and qj of capacitors C,, C2, and C3, respectively e. (5) Calculate the total energy Ug of all three capacitors when the switch S is connected to point B. C3 C2

Explanation / Answer

(A) Q = C V = 3 uF x 12 = 36 uC

(B) U1 = U2 = 0

U3 = C V^2 /2 = (3 x 10^-6)(12^2)/2

U = U1 + U2 + U3 = 2.16 x 10^-4 J

(C) C' = k C = 9 uF

Q = 108 uC

(D) C1 and C2 are in series,

C = C1 C2 /( C1 + C2) = 2/3 uF

potential across them will be same. say V

applying charge conservation,

36 = (2/3 + 3) V

V = 9.82 Volt

q1' = 6.5 uC

q2' = 6.5 uC

q3' = 29.5 uC

(e) U = (2/3 + 3) x 10^-6 x 9.82^2 /2

U = 1.77 x 10^-4 J

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