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Course Home sa MasteringPhysics:HW-Ch07 × CSecure https://session.masteringphysi

ID: 1792823 • Letter: C

Question

Course Home sa MasteringPhysics:HW-Ch07 × CSecure https://session.masteringphysics.com/myct/itemView?assignmentProblemID-85815829&offset; next HW-Ch0z Item 8 Resources « previous 8 of 10 I next s Item 8 Part A A 0.500-kg block, attached to a spring with length 0.60 m and force constant 40.0 N/m, is at rest with the back of the block at point A on a frictionless, horizontal air table (the figure (Figure 1) ). The mass of the spring is negligible. You move the block to the right along the surface by pulling with a constant 20.0-N horizontal force. What is the block's speed when the back of the block reaches point B, which is 0.25 Im to the right of point A? Express your answer using two significant figures. Submit My Answers Give Up Part B When the back of the block reaches point B, you let go of the block. In the subsequent motion, how close does the block get to the wall where the left end of the spring is attached? Express your answer using two significant figures. Figure 1 of 1 m from the wall Submit My Answers Give Up -0500kg 40.0 N/m 20,0 N 0.0 m 0.25 m

Explanation / Answer

Part A )

using work - energy theorem

KA + UA + Wother = KB + UB

KB = Wother + ( KA + UA ) - UB   

1/2 m VB2 = F dx - 0.5 k dx2

VB = ( 2 X ( F dx - 0.5 X k X dx2 ) / m )1/2

VB = ( 2 X ( 20 X 0.25 - 0.5 X 40 X 0.252 ) / 0.5 )1/2  

VB = 3.870 m/sec

Part B )

sameway

KC + UC = KB + UB

dx' = ( 2 ( KB + UB - KC ) / k )1/2

KB + UB = 0.5 X 0.5 X 3.8702 + 0.5 X 40 X 0.252

= 5 J

dx ' = ( 2 X ( 5 - 0 ) / 40 )1/2

dx ' = 0.5 m

so the point C and the wall is 0.6 - 0.5 = 0.1 m from the wall.