Class Management Help Chapter 11 Rotational Motion Dynamics Extension Regin Date
ID: 1793488 • Letter: C
Question
Class Management Help Chapter 11 Rotational Motion Dynamics Extension Regin Date: 1123201710:00:00 PM - Due Date: 11/27/2017 11:59:00 PM End Date: 11/272017 11:59:00 PM (10%) Problem 9: Suppose yoll start an antique car by exerting a force of 280 N on its crank for 0.16 s. Randomized Variables f= 280 N t= 0.16s d= 0.22 m G> what angular momentim 1s given to the engine if the handle of the crank 1s 0.22 m rom the pivot and the force is exerted to create maximum torque the entire time? Grade Summary Potential Submisslons 0% 100% () | 7 | 8 sin() cos() tanO cotanasin0 atan acotansinh) coshtanh) cotanh acoso (1% per attempt) detailed vicw Degrees O Radians Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 1% deduction per feedback.Explanation / Answer
Given
F = 280 N
t = 0.16 s
d = 0.22 m
we knwo that by definition of Torque T = d X F = r*F sin theta = d*F = I*alpha
where I is moment of inertia and alpha is angular acceleration
and angular momentum is L = I*W
the angular acceleration is alpha = W/t ==> W = alpha*t
L = (I*alpha)*t
L = (d*F)(t)
substituting the values
L = (0.22*280)(0.16) N m s
L = 9.856 N ms