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Predict&Explain; You push two identical bricks across a tabletop with constant s

ID: 1795228 • Letter: P

Question

Predict&Explain; You push two identical bricks across a tabletop with constant speed, v, as shown in Figure 5.27. In case 1 you place the bricks end to end in case 2 you stack the bricks one on top of the other (a) Is the force of kinetic friction in case 1 greater than, less than, or equal to the force of kinetic friction in case 2? (b) Choose the best explanation from among the following: A. The normal force in case 2 is larger, and thus the bricks press down more firmly against the tabletop. B. The normal force is the same in the two cases, and friction is independent of surface area. C. The bricks in case 1 have more surface area in contact with the tabletop, and this results in greater friction. 94.

Explanation / Answer

a] kinetic friction = uN where N = 2mg in both case where m is mass of one brick.

So friction will be equal.

b] B explaination is correct.