Steam enters an adiabatic turbine at 10 MPa and 500degrees C, and leaves at 10 k
ID: 1815111 • Letter: S
Question
Steam enters an adiabatic turbine at 10 MPa and 500degrees C, and leaves at 10 kPa with a quality of 90 percent.Neglecting the changes in kinetic and potential energies, determinethe mass flow rate required for a power output of 5 megawatts.Please show all steps.This is a lifesaver question. Thank you. Steam enters an adiabatic turbine at 10 MPa and 500degrees C, and leaves at 10 kPa with a quality of 90 percent.Neglecting the changes in kinetic and potential energies, determinethe mass flow rate required for a power output of 5 megawatts.Please show all steps.
This is a lifesaver question. Thank you.
Explanation / Answer
The first law for open systems is, q - w =mflowrate( h + ke + pe ). Neglecting ke and pe, and knowing that q = 0 since theturbine is adiabatic, the equation becomes -w =mflowrate( h2 - h1 ) From the steam tables, you can see that for superheated water at 10MPa, the sat. temp is 311 C. We are well above that, so thatconfirms that the steam is superheated. h1 from the tables = 3375.1 kJ/kg For h2, we have a quality value, so we know that itssaturated liquid-vapor mixture with x = 0.9. From the equation h2 = hf + xhfg,we can find h2. You have all you need to solve theproblem now. I'll let you take over from here. Hope I've helped.