Steam enters the condensor of a modern power plant at apressure of 1 psia and a

Question

Steam enters the condensor of a modern power plant at apressure of 1 psia and a quality of 0.98. The condensateleaves at 1 psia and 80 F. Determine (a) the heatrejected per pound and (b) the change in specific volume betweeninlet andoutlet.                   

Assumptions:
- Open system (condensor)
- Steady flow device (heat exchanger) - Minimal Friction - KE=0; PE=0 - Uniform velocity profiles - non ideal fluid (steam) - is not const. v1 does not equalv2 Steam enters the condensor of a modern power plant at apressure of 1 psia and a quality of 0.98. The condensateleaves at 1 psia and 80 F. Determine (a) the heatrejected per pound and (b) the change in specific volume betweeninlet andoutlet.                   

Assumptions:
- Open system (condensor)
- Steady flow device (heat exchanger) - Minimal Friction - KE=0; PE=0 - Uniform velocity profiles - non ideal fluid (steam) - is not const. v1 does not equalv2

Explanation / Answer

entrance pressure P1=1psia quality x1=0.98 condensate leaving the condenser maynot be in saturated staterather it is compressed liquid region at P1=1psia h1=hf+x1hfg    =69.74+0.98*1036    =1085.02Btu/lb specific volumev1=vf+x1vfg                            =0.01614+0.98(333.6-0.01614)                             =326.928ft3/lb exit condition at P2=1psia andT2=80F from compressed liquid region h2=49.44Btu/lb v2=0.01602ft3/lb a) heat rejected per pound q=h1-h2    =1085.02-49.44    =1035.58Btu/lb b)change in specific volume v=v1-v2                                             =326.928-0.01602                                             =326.91198ft3/lb I hope this helps best of luck with rest of your coursework                                             =326.928-0.01602                                             =326.91198ft3/lb I hope this helps best of luck with rest of your coursework

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