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In the double-slit experiment of Figure below, the electric fields of the waves

ID: 1863647 • Letter: I

Question

In the double-slit experiment of Figure below, the electric fields of the waves arriving at point P are given by the following equation, where time t is in seconds.

E1 = (2.61 ?V/m) sin[(1.47 × 1015)t]

E2 = (2.61 ?V/m) sin[(1.47 × 1015)t + 39.4 rad],

(a) What is the amplitude of the resultant electric field at point P? (b) What is the ratio of the intensity IP at point P to the intensity Icen at the center of the interference pattern? In a phasor diagram of the electric fields, (c) at what rate would the phasors rotate around the origin and (d) what is the angle between the phasors, in rads?

Incident wave (6) Sko (b) Path length difference AL (a)

Explanation / Answer

Part a)

sina + sin(a+b) = 2cos(b/2)sin(a+b/2)

E1 + E2 = 2Eocos(phi/2)sin(2t+phi/2)

E = 2Eocos(phi/2)

Eo = 2.61 uV/m

phi = 39.4 rad

E = 3.44 uV/m

part b )

I = 4Iocos^2(phi/2) = 1.74 Io

Icenter = 4Iocos^2(0) = 4Io

I/Icenter = 0.435

part c)

rate = w = 1.47 x 10^15 rad/s

part d )

angle = 39.4 rad