Consider three charges arranged as shown. What is the electric field at a point

Question

Consider three charges arranged as shown. What is the electric field at a point 1.29 cm to the left of the middle charge? The acceleration due to gravity is 9.8 m/s 2 . The Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of N/C.

Consider three charges arranged as shown. 5.67 AC 2.34 C 5 C 2.62 cm2.13 cm What is the electric field at a point 1.29 cm to the left of the middle charge? The accelera tion due to gravity is 9.8 m/s. The Coulomb constant is 8.98755 x 10 N m/C Answer in units of N/C

Explanation / Answer

Net electric field at the given point

E= electric field due to left charge - electric field due to middle charge+ electric field due to right charge

= K [ 5.67/((2.62- 1.29)*10^-2)^2- 2.34/(1.29*10^-2)^2+4.25/((2.13+1.29)*10^-2)^2 ]*10^-6

E= 1.946*10^8 N/C

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Comment in case any doubt..goodluck

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