MasteringPhysics: 02-Ch 18-Google Chrome Secure https:// ngphysics.com/myct/item

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MasteringPhysics: 02-Ch 18-Google Chrome Secure https:// ngphysics.com/myct/itemView?assignmentProblemID-92123281&toffset-next; Q2-Ch 18 Multiple Choice Question 18.29 C6 of8 Part A Each plate of a parallel-plate air capacitor has an area of 0.0040 m2, and the separation of the plates is 0 080 mm. An electric field of 79 105 Vim is present between the plates. The surface charge density on the plates, in uC/m2, is closest to 110 150 180 o 70 35 Submit Request Answer Next > Provide Feedback

Explanation / Answer

Voltage across capacitor

V=Ed =7.9*106*0.08*10-3=632 Volts

Capacitance

C=eoA/d =(8.8542*10-12)(0.004)/(0.08*10-3)

C=4.427*10-10F

Charge

Q=CV=(4.427*10-10)(632)=2.8*10-7 C

surface charge density

sigma =Q/A=2.8*10-7/0.004=7*10-5C/m2

Sigma=70 uC/m2

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