Please thoroughly explain how you got to each step, and how you got the answer.

Question

Please thoroughly explain how you got to each step, and how you got the answer. Thank you!

An electron is a subatomic particle (m-9xl0 kg) that is subjected to electrie forces. An electron moving in the +x direction accelerates from an initial velocity 5.56x10' m/s to a final velocity 2.07x10 m's while traveling a distance of 0.037 m. The e acceleration is due to two electric forces parallel to the x axis: F 7.87x10" N and Fa which points in the -x direction. Find the magnitude of the net force Fiet acting on the electron AND the electrie force Fa lectron's

Explanation / Answer

Given that,

u = 5.56*10^5 m/s

v = 2.07*10^6 m/s

d1 = 0.037 m

F1 = 7.87*10^(-17) N

From kinematic equation,

v^2 - u^2 = 2as

(2.07*10^6)^2 - (5.56*10^5)^2 = 2*a*0.037

acceleration, a = 5.37*10^13 m/s^2

Net force,

Fnet = ma

Fnet = 9.1*10^(-31) * 5.37*10^13

Fnet = 4.88*10^(-17) N

(b)

Fnet = F1 + F2

so, F2 = Fnet - F1

F2 = 4.88*10^(-17) - 7.87*10^(-17)

F2 = -2.99*10^(-17) N

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