Problem 18.72 What is the capacitance? Constants A parallel-plate air capacitor
ID: 1878162 • Letter: P
Question
Problem 18.72 What is the capacitance? Constants A parallel-plate air capacitor is made from two plates 0.175 m square, spaced 0.795 cm apart. It is connected to a 120 V battery. If the plates are pulled apart to a separation of 1.59 cm, suppose the battery remains connected while the plates are pulled apart. C 3.41 10 11 DE Submit Previou Answers RequestAnswer X Incorrect; Try Again; 2 attempts remaining Part B What is the charge on each plate? nC Submit Reavest Answer PartC What is the electric field botween the plates?Explanation / Answer
1.96133E-10 Farad
196 pF
The charge on each plate = Q = CV = 196 pF * 120 = 23520E-12 C = 23.52 E -9 Coulomb
Capactance C = 0A/d = (8.854 E-12*0.175)/(0.0079) =1.96133E-10 Farad
196 pF