Part A Determine the magnitude of the resultant force FR-F1 + F2 Assume that Fi-

Question

Part A Determine the magnitude of the resultant force FR-F1 + F2 Assume that Fi-225 lb and F2 = 390 lb . (Figure 1) Express your answer to three significant figures and include the appropriate units Fr Vale Units Submit Request Answer Part B 1 of 1> 1 of 1 Determine the direction of the resultant force FR, measured counterclockwise from the positive r axis. Express your answer to three significant figures and include the appropriate units 30 | : | Value Units Submit Request A F2 Return to Assignment Provide Feedback

Explanation / Answer

Lets resolve the vector F1 into components

angle from positive x axis, = 60.0

F1x = F1 * cos

= 225.0 * cos(60.0)

= 112.5 lb

F1y = F1 * sin

= 225.0 * sin(60.0)

= 194.8557 lb

Lets resolve the vector F2 into components

angle from positive x axis, = -45.0

F2x = F2 * cos

= 390.0 * cos(-45.0)

= 275.7716 lb

F2y = F2 * sin

= 390.0 * sin(-45.0)

= -275.7716 lb

we have:

F1 = 112.5i+ 194.8557j

F2 = 275.7716i- 275.7716j

FR = F1 + F2

FR = (112.5i+ 194.8557j) + (275.7716i- 275.7716j)

= (F1x + F2x)i + (F1y + F2y)j

= (112.5 + 275.7716)i + (194.8557 - 275.7716)j

= 388.2716i- 80.9159j

A)

magnitude of FR = sqrt (388.2716^2 + -80.9159^2)

magnitude of FR = 396.6135 lb

Answer: 397 lb

b)

Since x component is positive and y component is negative

It lies in the 4th cordinate

angle = 270 + atan(|x/y|)

angle = 270 + atan(|388.2716/-80.9159|)

angle = 348 degree

Answer: 348 degree

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