PartA The conducting box in the figure (Figure 1)has been given an excess negati
ID: 1879519 • Letter: P
Question
PartA The conducting box in the figure (Figure 1)has been given an excess negative charge. The surface density of excess electrons at the center of the top surface is 5.00x1010 electrons/m2 What is the electric field strength E1 at point 1? Express your answer to three significant figures and include the appropriate units. alue Units Submit t Answer Part B What is the electric field strength E2 at point 2? Express your answer as an integer and include the appropriate units. alue Units Submit t Answer Part C Figure 1 of 1 What is the electric field strength Es at point 3? Express your answer as an integer and include the appropriate units. alue UnitsExplanation / Answer
Point 1:
All the charge resides on the surface
E = Surface Charge density/permittivity
E = [(5 x 1010 electrons/m2)*(1.602 x 10-19 / 1 electron)]/(8.854 x 10-12 C2/N-m2)
E = 904.67 N/C
E1 = 904 N/C
Point 2:
E2 is inside the conductor and will be zero. Consider a Gaussian surface surrounding any portion inside the conductor. There will be no charge enclosed
E2 = 0 N/C
Point 3:
E3 is also inside the conductor and will be zero. Consider a Gaussian surface surrounding any location inside the hollow portion of the conductor. There will be no charge enclosed
E3 = 0 N/C