PartA What is the electric field at point 1 in the figure? Give your answer in c
ID: 1882104 • Letter: P
Question
PartA What is the electric field at point 1 in the figure? Give your answer in component form.(Figure 1)Assume that a 2.0 cm b 0.70 cm, and q 4.4 nC Express your answer using two significant figures. Enter your answers numerically separated by a comma. Assume that r-axis is directed horizontally to the right, and the y- axis is directed vertically upward E1x Ely N/C Submit RequestAnswer Part B What is the electric field at point 2 in the figure? Give your answer in component form. Express your answer using two significant figures. Enter your answers numerically separated by a comma. Assume that r-axis is directed horizontally to the right, and the y- axis is directed vertically upward N/C Submit RequestAnswer Part C What is the electric field at point 3 in the figure? Give your answer in component form. Express your answer using two significant figures. Enter your answers numerically separated by a comma. Assume that -axis is directed horizontally to the right, and the y- axis is directed vertically upward Figure 1 of 1 3x N/C Submit Request Answer Provide Feedback Next >Explanation / Answer
Concept : From Gauss's Law for a point charge in the above case the elctric field decreases with square of the distance from the charge.
Formula used :E=1/40 * (q/R^2) R, where R is the vector from the point charge to the field point. Using geometry as a basis, it can often be written in terms of the coordinate system's unit vectors so that the equation for the electric field will be easier to solve.
Please note : 1/40 is a constant = 8.99×10^9 Nm^2 / C^2
1.) Consider the Point 1 from fig :-
Vector R1 = bx + ay ; That is 0.7x + 2y. [ Expressing point 1 in coordinate form ]
R1 = sqrt ( a^2 + b^2 ) [ The distance of point 1 from point charge q ].
Substituting the above in the Gauss Formula we have :-
E at point 1 = 8.99 * 10^9 * 4.4/(2^2 + 0.7^2) * (0.7x + 2y)
E at point 1 in component form = (E1x,E1y) = (63 * 10^6, 18 * 10^7) N/C
2.) Considering the point 2 :-
Vector R2 has only x component and no y.
R2 = b = 0.7 cm [ Distance of point 2 from point charge q ]
Substituting the Gauss's Formula we have :-
E2 = (8.99×10^9 Nm2/C2) * 4.4 / (0.7) ^ 2 in the x - direction.
E2 in component form = (E2x,0) = ( 80.8 * 10^11,0) N/C
3.) Considering the point 3 :-
This is very similar to the point 1 case :-
The only difference is the y- component is = - 2y
Vector R3 = bx - ay ; That is 0.7x - 2y. [ Expressing point 1 in coordinate form ]
R3 = sqrt ( a^2 + b^2 ) [ The distance of point 1 from point charge q ].
Substituting the above in the Gauss Formula we have :-
E3 = 8.99 * 10^9 * 4.4/(2^2 + 0.7^2) * (0.7x - 2y)
E3 in component form = (E3x,E3y) = (63 * 10^6, -18 * 10^7) N/C