In the figure below mi 179 N. 14 kg and m2 - 9 kg. The kinetic coefficient of fr
ID: 1884834 • Letter: I
Question
In the figure below mi 179 N. 14 kg and m2 - 9 kg. The kinetic coefficient of friction between m and the floor is 0.3 and that between m2 and the floor is 0.5. You push with a force of magnitude F- m1 112 Part 1 Your answer is incorrect. Try again. a) What is the acceleration of the center of mass? (Enter the magnitude.) the tolerance is +/-596 Attempts: 1 of 10 used SAVE FOR LATER SUBMIT ANSWER Part 2 x Your answer is incorrect. Try again. (b) What is the magnitude of the force that mi exerts on m2? IN the tolerance is +/-5%Explanation / Answer
a] By newtons second law, a = Fnet/mtotal
= [Fapplied - u1m1g - u2m2g]/[m1+m2]
= [ 179 - 0.3*14*9.8 - 0.5*9*9.8]/[14+9]
= 4.076 m/s^2
b] again using force equation on m2,
N - u2m2g = m2a
N = u2m2g + m2a
= 0.5*9*9.8 + 9*4.076
= 80.78 N answer